Android - 撥號字串 android_secret_code

如何在Android中 撥號程式裡面 打入特別字串 就會出現測試模式
Android中 這個號碼有固定格式 *#*# 開頭，#*#*結尾的撥號字串

Ex:進入撥號程式，輸入*#*#4636#*#* 可以看到一個測試發佈文章應用
Step:1. AndroidManifest.xml添加Filter就可以
<br><receiver android:name="TestingSettingsBroadcastReceiver"><br> <intent-filter><br> <action android:name="android.provider.Telephony.SECRET_CODE" /><br> <data android:scheme="android_secret_code" android:host="4636" /><br> </intent-filter><br> </receiver><br>

2. Write a class: TestingSettingsBroadcastReceiver
<br>public class TestingSettingsBroadcastReceiver extends BroadcastReceiver { //繼承 BroadcastReceiver<br>public TestingSettingsBroadcastReceiver() { } <br><br>@Override <br>public void onReceive(Context context, Intent intent)<br>{ <br>if (intent.getAction().equals(SECRET_CODE_ACTION))<br>{ //new a Intent for next activity<br>Intent i = new Intent(Intent.ACTION_MAIN); <br>i.setClass(context, >TestingSettings.class); // next activity class<br>i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); <br>context.startActivity(i); <br>} <br>} <br>}<br>
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查看Phone的原始程式碼 SpecialCharSequenceMgr.java，
有一個函數專門處理*#*# 開頭，#*#*結尾的撥號字串。

<br>/**<br>* Handles secret codes to launch arbitrary activities in the form of *#*##*#*.<br>* If a secret code is encountered an Intent is started with the android_secret_code://<br>* URI.<br>*<br>* @param context the context to use<br>* @param input the text to check for a secret code in<br>* @return true if a secret code was encountered<br>*/<br>static private boolean handleSecretCode(Context context, String input) {<br>// Secret codes are in the form *#*##*#*<br>int len = input.length();<br>if (len > 8 && input.startsWith("*#*#") && input.endsWith("#*#*")) {<br>Intent intent = new Intent(Intents.SECRET_CODE_ACTION,<br>Uri.parse("android_secret_code://" + input.substring(4, len - 4)));<br>context.sendBroadcast(intent);<br>return true;<br>}<br><br>return false;<br>}<br>
Reference:
http://android.amberfog.com/?p=422
http://blog.csdn.net/learnrose/article/details/6223048